एक 400V, 3-फेज, स्टार-संयोजित तुल्यकालिक मोटर में 0.04 OHMS के प्रभावी प्रतिरोध पर 200A की आर्मेचर धारा है। अर्ध-पूर्ण भार पर लघु परिपथ भार क्षय _________ होगा।

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SSC JE Electrical 06 Jun 2024 Shift 2 Official Paper - 1
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  1. 2100 W
  2. 2000 W
  3. 1000 W
  4. 1200 W

Answer (Detailed Solution Below)

Option 4 : 1200 W
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Detailed Solution

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सिद्धांत

तांबे का क्षय इस प्रकार दिया गया है:

P1 = I2 x R

आधे भार पर:

P2 = (0.5I)2 x R = 0.25(I2 x R)

आधे भार पर लघु परिपथ भार क्षय होगा:

P = 0.25(I2 x R) - (I2 x R) = -0.75(I2 x R)

केवल परिमाण पर विचार करके:

P = 0.75(I2 x R)

गणना

दिया गया है, I = 200A

R = 0.04Ω

P = 0.75 x (200)2 x 0.04

P = 1200 W

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