Question
Download Solution PDFForce on a current-carrying conductor will be _________ when it is placed at right angles to the direction of the magnetic field.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
The force on a current-carrying wire in a magnetic field is given by:
\(F= ilb \space sin\theta\)
where, F = Force
i = Current
l = Length
b = Magnetic field
Concept
If the angle between the force and the magnetic field is 90°, then sin90 = 1.
\(F= ilb \space sin90\)
F = ilb = Fmax
The force on a current-carrying conductor will be maximum when it is placed at right angles to the direction of the magnetic field.
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.