Question
Download Solution PDFFollowing IS : 2502-1963, determine the approximate total length of bar of 6 mm diameter, measured along centre line, for the stirrup shown in Figure. (Note : Take the given stirrup dimensions in Figure as internal).
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
As per, Indian Standard (IS) 2502:1963,
Total length of bar(L) = 2(A + E) + 24d
From the given figure ;
E = 11 cm = 110 mm
A = 26 cm = 260 mm
24d:
- d: This refers to the diameter of the bar used, in this case, a 6 mm diameter bar.
- : This term represents the additional length required for the bends and hooks in the stirrup.
- According to IS 2502:1963, hooks are typically provided at the ends of stirrups to ensure that the stirrup is anchored properly within the concrete.
- The length of each hook is calculated for standard length of a 90° bend is .
- For two hooks (one at each end), the total length required for the hooks is .
Total length of bar
L = 2 × (110 + 260) + 24 × 6 = 884 mm = 0.884 m
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