Find the area of a square whose diagonal is 98 cm. ( in cm²)

Given:

Diagonal of a square = 98 cm

Formula used:

Pythagorean theorem: \(c^2 = a^2 + b^2\), where c is the hypotenuse (diagonal of the square), and a and b are the lengths of the other two sides (the sides of the square).

Area of square = (side)²

Calculation:

Let x be the length of one side of the square.

From the Pythagorean theorem, we have:

\(x^2 + x^2 = 98^2\)

\(2x^2 = 9604\)

\(x^2 = 4802\)

Therefore, the area of the square is:

Area = x²

Area = 4802 cm²

∴ Option 2 is the correct answer.