Question
Download Solution PDFDetermine the minimum thickness of the rectangular axial bar shown against yielding. Given Factor of Safety (FOS) = 2 and Yield stress = 310 MPa.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
To prevent yielding, the actual stress on the material must be less than or equal to the allowable stress (yield stress divided by the factor of safety).
Given:
- Axial load, P = 120 kN = 120000 N
- Width of bar, b = 40 mm
- Yield stress, σyield = 310 MPa
- Factor of Safety, FOS = 2
Step 1: Allowable Stress
\(\sigma_{\text{allowable}} = \frac{310}{2} = 155~\text{MPa}\)
Step 2: Use axial stress formula
\(\sigma = \frac{P}{A} = \frac{P}{bt}\) → \(t = \frac{P}{b \cdot \sigma_{\text{allowable}}}\)
\(t = \frac{120000}{40 \cdot 155} = \frac{120000}{6200} = 19.35 \approx 19.4~\text{mm}\)
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.