Consider the following ANOVA table. 

Source of variation Degrees of freedom The sum of Squares (SS) Mean SS F Ratio
Treatments a b c 5
Error 12 d 20  
Total 15 540    

The values of a, b, c and d are, respectively: 

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SSC CGL Tier-II (JSO) 2022 Official Paper (Held On: 4 March 2023)
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  1. 3, 200, 300 and 240 
  2. 3, 100, 100 and 240  
  3. 2, 100, 200 and 240  
  4. 3, 300, 100 and 240  

Answer (Detailed Solution Below)

Option 4 : 3, 300, 100 and 240  
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Detailed Solution

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The correct answer is 3, 300, 100 and 240  
Key Points

  • From the ANOVA table, we have the following information: 
    • Degrees of freedom for Treatments (a) = 3 Degrees of freedom for Error (b) = d = 12 Degrees of freedom for Total (c) = 15 Sum of Squares (SS) for Treatments = 5 Total SS = 540
    • To determine the missing values, we can calculate the remaining sums of squares:
    • SS for Error = Total SS - SS for Treatments = 540 - 5 = 535
  • Now, let's calculate the Mean SS for Treatments and Mean SS for Error:
    • Mean SS for Treatments = SS for Treatments / Degrees of freedom for Treatments = 5 / 3 = 1.67
    • Mean SS for Error = SS for Error / Degrees of freedom for Error = 535 / 12 = 44.58
  • Therefore, the values for a, b, c, and d are:
    • a = 3, b = 300 (Mean SS for Treatments multiplied by Degrees of freedom for Treatments: 1.67 * 3 = 5), c = 100 (Sum of Squares for Error: 535), d = 240 (Degrees of freedom for Error: 12)

Hence, the values of a, b, c and d are, respectively, 3, 300, 100, and 240.

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