Anand covers a certain distance in the first lag of 5 hours at the speed of 50 km/h. In the second lag, he increased the speed by 20% due to which he covered 20% extra distance than that of the first lag. He covered the third lag at the average speed of the first two lags and covered 10% extra distance than that of the second lag distance. How much total time (in hours) did he take to complete all three lags?

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SSC CGL 2023 Tier-I Official Paper (Held On: 21 Jul 2023 Shift 1)
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  1. 16
  2. 15
  3. 18
  4. 14

Answer (Detailed Solution Below)

Option 1 : 16
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Detailed Solution

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Given

Time = 5 hours

Speed = 50 km/hr

Formula used

Speed = Distance/Time

Calculation

Distance = 50 × 5 = 250 km

In the second lag:

Distance = 250 + 250 × 120/100 = 300 km

Speed = 50 + 50 × 120/100 = 60 km/hr

Time = 300/60 = 5 hours

In the third lag:

Distance = 300 + 300 × 110/100 = 330 km

Speed = (60 + 50)/2 = 55 km/hr

Time = 330/55 = 6 hours

Total time = 5 + 5 + 6 = 16 hours

The answer is 16 hours.

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