Question
Download Solution PDFAn RLC series circuit has R =2 Ω, C = 20 μF and the inductance is adjusted such that the voltage across the resistance is maximum. If the applied voltage is 10 V at a frequency of 1000 rad/sec, then find the value of inductance L.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
- For a series RLC circuit at resonance, the inductive reactance becomes equal to the capacitive reactance.
- Thus, at the time of resonance, the circuit behaves as a purely resistive circuit.
- The value of resonant frequency is given by:
\(ω_c=\frac{1}{\sqrt{LC}}~rad/sec\)
Calculation:
For the given question; R = 2 Ω, ωc = 1000 rad/sec, C = 20 μF
\(ω_c=\frac{1}{\sqrt{LC}}~rad/sec\)
\(1000= \;\frac{1}{{\sqrt {L \times {{20}^{ - 6}}}}}\)
⇒ L = 0.05 H
Last updated on Jun 16, 2025
-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.
-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.
-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31.
-> Candidates with a degree/diploma in engineering are eligible for this post.
-> The selection process includes Paper I and Paper II online exams, followed by document verification.
-> Prepare for the exam using SSC JE EE Previous Year Papers.