An AC circuit has R = 100 Ω, C = 2 μF and L = 80 mH, connected in series. The quality factor of the circuit is

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  1. 2
  2. 0.5
  3. 20
  4. 400

Answer (Detailed Solution Below)

Option 1 : 2
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Calculation:
The formula for the quality factor (Q) of an LC circuit is given by:

Q = (1 / R) × √(L / C)

Where:

  • R = resistance = 100 Ω
  • L = inductance = 80 mH = 80 × 10-3 H
  • C = capacitance = 2 μF = 2 × 10-6 F

Substituting the values into the formula:

Q = (1 / 100) × √((80 × 10-3) / (2 × 10-6))

Q = (1 / 100) × √(40 × 103)

Q = (1 / 100) × 200

Q = 2

The quality factor of the circuit is 2.

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