A policeman sees a chain snatcher at a distance of 500 m. He starts chasing the chain snatcher who is running with a speed of 5 m/s while the policeman is chasing him with a speed of 15 m/s. What is the distance covered by the chain snatcher when he is caught by the policeman?

Question

Question

This question was previously asked in

SSC CGL 2022 Tier-I Official Paper (Held On : 03 Dec 2022 Shift 3)

Answer 1

Given:

A policeman sees a chain snatcher at a distance of 500 m.

Speed of the snatcher = 5 m/s

Speed of the policeman = 15 m/s

Concept used:

1. Time taken to meet for two objects coming towards each other = Intermediary distance ÷ Relative speed

2. Relative speed is the difference between individual speeds while two objects run in the same direction.

3. Distance = Speed × Time

4. km/h = 5/18 m/s

Calculation:

Time taken to catch the snatcher by the policeman = 500 ÷ (15 - 5) = 50 seconds

F1 SSC Amit A 24-02-2023 D6

Now, the distance covered by the chain snatcher when he is caught by the policeman = 50 × 5 = 250 m

∴ The distance covered by the chain snatcher when he is caught by the policeman is 250 m.