A Lissajous patterns on a Cathode Ray Oscilloscope (CRO) has 8 vertical maximum values and 4 horizontal maximum values. The frequency of the horizontal input is 1600 Hz. Determine the frequency of the vertical input?

This question was previously asked in
SSC JE Electrical 07 Jun 2024 Shift 3 Official Paper - 1
View all SSC JE EE Papers >
  1. 200 Hz
  2. 800 Hz
  3. 600 Hz
  4. 400 Hz

Answer (Detailed Solution Below)

Option 2 : 800 Hz
Free
RRB JE CBT I Full Test - 23
14.2 K Users
100 Questions 100 Marks 90 Mins

Detailed Solution

Download Solution PDF

Concept

The unknown to the known frequency for Lissajous patterns on a Cathode Ray Oscilloscope (CRO) is given by:

\(f_y=f_x({n_x\over n_y})\)

where, fy = Vertical frequency

fx = Horizontal frequency

nx = No. of horizontal tangencies

ny = No. of vertical tangencies

Calculation

Given, ny = 8 and nx = 4

fx = 1600 Hz

\(f_y=1600\times ({8\over 16})\)

fy = 800 Hz

Latest SSC JE EE Updates

Last updated on May 29, 2025

-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

Get Free Access Now
Hot Links: teen patti jodi teen patti master 2025 teen patti master plus teen patti rules