Question
Download Solution PDFA conical cap has the base diameter 24 cm and height 16 cm. What is the cost of painting the surface of the cap at the rate of 70 paisa per square cm?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven
Diameter of conical cap = 24 cm
Height of conical cap = 16 cm
Formula used
Curved surface area of cone = πrl
l2 = r2 + h2
Where, l = slant height of the cone
r = radius of the cone
h = height of the cone
Calculation
Diameter of conical cap = 24 cm
Radius of conical cap = 12 cm
Now, l2 = r2 + h2
⇒ l2 = (122 + 162)
⇒ l2 = (144 + 256)
⇒ l2 = 400 cm2
⇒ l = 20 cm
The curved surface area of the cone = πrl
⇒ (\(\frac{22}{{7}}\) × 12 × 20) cm2
⇒ \(\frac{5280}{{7}}\) cm2
The cost of painting the surface of the cap
⇒ Rs. (\(\frac{5280}{{7}}\) × 70/100) [1 rupee = 100 paisa]
⇒ Rs. 528
∴ The cost of painting the surface of the cap is Rs. 528.
Last updated on Jun 26, 2025
-> The Staff selection commission has released the SSC CHSL Notification 2025 on its official website on 23rd June 2025.
-> The SSC CHSL Apply Online 2025 has been started and candidates can apply online on or before 18th July.
-> The SSC has released the SSC CHSL exam calendar for various exams including CHSL 2025 Recruitment. As per the calendar, SSC CHSL Application process will be active from 23rd June 2025 to 18th July 2025.
-> The SSC CHSL is conducted to recruit candidates for various posts such as Postal Assistant, Lower Divisional Clerks, Court Clerk, Sorting Assistants, Data Entry Operators, etc. under the Central Government.
-> The SSC CHSL Selection Process consists of a Computer Based Exam (Tier I & Tier II).
-> To enhance your preparation for the exam, practice important questions from SSC CHSL Previous Year Papers. Also, attempt SSC CHSL Mock Test.
-> The UGC NET Exam Analysis 2025 for the exam conducted on June 25 is out.