A can of water and milk mixture contains 60% milk. A part of this mixture is replaced by another mixture containing 50% milk and the percentage of milk was found to be 52%. The quantity of mixture replaced is:

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SSC CGL 2022 Tier-I Official Paper (Held On : 13 Dec 2022 Shift 2)
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  1. \(1 \over 5\)
  2. \(3 \over 5\)
  3. \(4 \over 5\)
  4. \(2 \over 5\)

Answer (Detailed Solution Below)

Option 3 : \(4 \over 5\)
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Detailed Solution

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Given:

A can of water and milk mixture contains 60% milk. A part of this mixture is replaced by another mixture containing 50% milk and the percentage of milk was found to be 52%. 

Calculation:

Using mixture and alligation,

F1 SSC Amit A 09-03-2023 D14

So, the ratio of the original solution that has 60% milk concentration to the solution that has 50% milk concentration = 2 : 8 = 1 : 4

Now, the quantity of mixture replaced is

⇒ \(1 - \frac {1}{1 + 4}\)

⇒ \(4 \over 5\)

∴ The quantity of mixture replaced is \(4 \over 5\).

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