Question
Download Solution PDFWith an average speed of 45 km/h, a train reaches its destination on time. If it goes with an average speed of 30 km/h, it is late by 15 minutes. The total journey is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Actual speed = 45 km/h
Reduced speed = 30 km/h
Formula used:
Total distance = \(\frac{(S_1 × S_2)}{S_1-S_2} \times (T_1+T_2)\)
Here,
S1 = Actual speed
S2 = Reduced speed
T1 = Time1
T2 = Time 2
Calculation:
According to the concept,
Total distance = \(\frac{(45 × 30)}{45-30} \times (0+\frac{1}{4})\)
⇒ \(\frac{(1350)}{15} \times \frac{1}{4}\)
⇒ 22.5 km
∴ The distance between A and B is 22.5 km.
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