Question
Download Solution PDFWhat is the output of the following code?
int i = 1 ;
while ( i <= 10 )
printf ( "%d\n", i );
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe correct option is 4
Concept:
Here’s the given code:
int i = 1;
while (i <= 10)
printf("%d\n", i);
The condition i <= 10 is true for i = 1.
The printf() statement runs and prints 1.
But there is no increment (i++) inside the loop.
The variable i is initialized to 1. The while loop continues if the condition i <= 10 is true.
However, no statement within the loop increments the value of i.
Therefore, the value of i will always remain 1, and the condition i <= 10 will always be true, causing the printf statement to execute repeatedly without ever reaching a termination condition. It will continuously print "1" followed by a newline character.
Last updated on Jun 7, 2025
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