Question
Download Solution PDFThe lines p(p2 + 1)x − y + q = 0 and (p2 + 1)2x + (p2 + 1)y + 2q = 0 are perpendicular to a common line for
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation
Given:
The lines p(p² + 1)x - y + q = 0 and (p² + 1)x + (p² + 1)y + 2q = 0 are perpendicular to a common line.
Then these lines must be parallel to each other.
∴ m₁ = m₂ ⇒ -\(\frac{p(p^2+1)}{-1}\) = -\(\frac{(p^2+1)^2}{p^2+1}\)
⇒ (p² + 1)(p + 1) = 0
⇒ p = -1
Hence option 1 is correct
Last updated on Jul 3, 2025
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