The frustum of a right circular cone has the radius of the base as 5 cm, radius of the top as 3 cm, and height as 6 cm. What is its volume?

This question was previously asked in
SSC CHSL 2021 (Held On : 27 May 2022 Shift 2)
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  1. 98 π cm3
  2. 100 π cm3
  3. 96 π cm3
  4. 90 π cm3

Answer (Detailed Solution Below)

Option 1 : 98 π cm3
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SSC CHSL Exam 2023 Tier-I Official Paper (Held On: 02 Aug 2023 Shift 1)
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100 Questions 200 Marks 60 Mins

Detailed Solution

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Given:

Radius of the base (R) = 5 cm 

Radius of the top (r) = 3 cm

Height (H) of frustum = 6 cm

Formula used:

Volume of Frustum (V) = 1/3 πH (R2 + Rr + r2)

Calculations:

According to the question,

Volume of Frustum = 1/3 π × 6 × [(5)2 + (5 × 3) + (3)2]

⇒ V = π × 2 × [25 + 15 + 9]

⇒ V = π × 2 × [49] = 98π cm3 

∴ The volume of frustum is 98π cm3. 

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