Question
Download Solution PDFThe equation for active power in a three-phase star connected circuit is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPower in 3ϕ circuit:
Case 1: In star connection
The active power is given by:
\(P=\sqrt{3}V_LI_L\space cos\phi\)
The reactive power is given by:
\(Q=\sqrt{3}V_LI_L\space sin\phi\)
The apparent power is given by:
\(S=\sqrt{P^2+Q^2}\)
\(S=\sqrt{3}V_LI_L\)
Case 2: In delta connection
The active power is given by:
\(P={3}V_PI_P\space cos\phi\)
The reactive power is given by:
\(Q={3}V_PI_P\space sin\phi\)
The apparent power is given by:
\(S=\sqrt{P^2+Q^2}\)
\(S=3V_PI_P\)
Here, VL and IL are line voltage and line current
Vp and Ip are phase voltage and phase current
Last updated on Jun 16, 2025
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