μ'(r) and μ'r represent the factorial moment of order r about the origin and rth moment about the origin of the distribution xi|fi, i = 1, 2, … n. The value of μ'2 equals to:

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SSC CGL JSO Tier-II, 2018 (Statistics) Official Paper-III (Held On: 14 Sept, 2019)
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  1. μ'(1)2
  2. μ'(2) - μ'(1)
  3. μ'(2) + μ'(1)
  4. μ'(2)

Answer (Detailed Solution Below)

Option 3 : μ'(2) + μ'(1)
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PYST 1: SSC CGL - English (Held On : 11 April 2022 Shift 1)
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Detailed Solution

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Explanation

The moment about origin of binomial distribution is given by

 μ'2 = E(X2) = ∑x2(n/x)pxqn – x

⇒ ∑{x(x – x) + x}[n(n – 1)/x(x – 1)](n – 2/x – 2)pxq3 – x

⇒ n(n – 1)p2[∑nx= 2(n – 2/x – 2)px – 2qn – x] + np

⇒ n(n -1)p2 × ( q + p)n – 2 + np

⇒ n(n – 1)p2 + np

⇒ n2p2 – np2 + np

Factorial moment of binomial distribution

μ’(r) = E(x(r)) = ∑nx = 0 × x2p(x)

⇒ ∑nx = 0 × x(r)[n!/x!(n – x)!] × px – rqn – r

⇒ n(r)prnx = r [(n – r)!/(x – r)(n – x)!] × px – rqn – x

⇒ n(r)pr(q+ p)n – r

⇒ n(r)p(r)      [ p + q] = 1

⇒ μ’(1) = E(x1)= np = mean

⇒ μ’(2) = E(x2) = n2p2 =n(n – 1)p2

⇒ n2p2 – np2

μ’(2) + μ’(1) = n2p2np2 + np

μ’(2)+ μ’(1) = μ’2

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