Question
Download Solution PDFपाईप A आणि पाईप B एक टाकी x दिवसात भरू शकतात. पाईप A टाकी (x + 4) दिवसात भरू शकते आणि पाईप B टाकी (x + 36) दिवसात भरू शकते. दोन्ही पाईप टाकीचा 1/3 भाग किती दिवसात भरू शकतात?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
पाईप A आणि पाईप B एक टाकी भरू शकतात = x दिवस
पाईप A टाकी भरू शकतो = (x + 4) दिवस
पाईप B टाकी भरू शकतो = (x + 36) दिवस.
वापरलेले सूत्र:
एकत्र काम करण्यासाठी लागणारा वेळ = √अतिरिक्त दिवसांचे उत्पादन
गणना:
पाईप A आणि पाईप B टाकी भरू शकतात = √4 × 36
⇒ x = √144
⇒ x = 12 दिवस
∴ दोन्ही पाईप टाकीचा 1/3 भाग भरू शकतात = 12/3 = 4 दिवस
Alternate Method
पाईप A आणि पाईप B टाकी भरू शकतात = (t1 × t2)/(t1 + t2)
⇒ x = (x + 4) × (x + 36)/(x + 4 + x + 36)
⇒ x(2x + 40) = x2 + 36x + 4x + 144
⇒ 2x2 + 40x = x2 + 40x + 144
⇒ x2 = 144
⇒ x = 12 दिवस
∴ दोन्ही पाईप टाकीचा 1/3 भाग भरू शकतात = 12/3 = 4 दिवसLast updated on Jul 8, 2025
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