एखादी वस्तू x = 0 मीटर आणि t = 0 सेकंदामध्ये विराम अवस्थेत सुरू होते. ती x – अक्षाच्या बाजूने 2 मी/से2 या स्थिर त्सवरणासह गतिमान आहे. 1 सेकंद आणि 5 सेकंद या वेळेदरम्यान तिचा सरासरी वेग किती आहे?

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RRB ALP Electrician 22 Jan 2019 Official Paper (Shift 1)
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  1. 2 मीटर/सेकंद
  2. 8 मीटर/सेकंद
  3. 6 मीटर/सेकंद
  4. 4 मीटर/सेकंद

Answer (Detailed Solution Below)

Option 3 : 6 मीटर/सेकंद
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Detailed Solution

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संकल्पना:

  • सरासरी वेग = एकूण विस्थापन/ एकूण वेळ कालावधी
  • गतीचे समीकरण:
  • v = u + at
  • v 2 = u 2 + 2as
  • s = ut + 1/2 at 2

गणना:

दिलेल्याप्रमाणे:

वेळ मध्यांतर = 5 s & 1 s, प्रारंभिक वेग u = 0, आणि, प्रवेग a = 2 मीटर/सेकंद2

जेव्हा एखादी वस्तू विश्रांतीपासून सुरू होते, तेव्हा 1 सेकंद आणि 5 सेकंदात एकूण अंतर कापले जाते,

s = ut + 1/2 at 2

वस्तू विश्रांतीवर आहे, म्हणून, u = 0 m/s.

s 2 - s 1 = 24 मीटर

एकूण घेतलेला वेळ, t = t 2 - t 1 = 5 - 1 = 4 सेकंद

सरासरी वेग = एकूण विस्थापन/ एकूण वेळ कालावधी

सरासरी वेग = 24/4 = 6 मीटर/सेकंद

वेळ 1 s आणि 5 s दरम्यानचा सरासरी वेग = 6 मीटर/सेकंद

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