In a synchronous motor, the value of coupling angle depends on:

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PGCIL DT Electrical 13 Aug 2021 Official Paper (NR I)
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  1. the back EMF
  2. the excitation of the rotor
  3. the amount of load met by the motor
  4. the speed of the rotor

Answer (Detailed Solution Below)

Option 3 : the amount of load met by the motor
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Synchronous Motor on Load:

  • In DC motors and induction motors, when the load increased causes the motor speed decreases.
  • The decrease in speed reduces the counter EMF which causes additional current is drawn from the source to carry the increased load at a reduced speed.
  • This action cannot take place in a synchronous motor because it runs at a constant speed (i.e., synchronous speed) at all loads.
  • When we apply mechanical load to a synchronous motor then the rotor poles fall slightly behind the stator poles while continuing to run at synchronous speed.
  • The angular displacement between stator and rotor poles (called torque angle α ) causes the phase of back EMF Eb to change with respect to supply voltage V. This increases the resultant EMF Er in the stator winding.
  • Consequently, stator current increases to carry the load.


The following points may be noted in synchronous motor operation:

  • A Synchronous motor runs at the synchronous speed at all loads. It meets the increased load not by a decrease in speed but by the relative shift between stator and rotor poles i.e., by the adjustment of torque angle α.
  • If the load on the motor increases, the torque angle α  also increases (i.e., rotor poles lag behind the stator poles by a greater angle) but the motor continues to run at synchronous speed.
  • The increase in torque angle α  causes a greater phase shift of back EMF Eb with respect to supply voltage V.
  • The greater phase shift of back EMF Eb with respect to supply voltage V cause increases the net voltage Er in the stator winding. Consequently, the armature current Iincreases to meet the load demand.
  • If the load on the motor decreases, the torque angle also decreases. This causes a smaller phase shift of Eb with respect to V. Consequently, the net voltage Er in the stator winding decreases and so does the armature current Ia.
  • Where Armature Current, \({I_a} = \frac{{V - {E_b}}}{{{Z_s}}} = \frac{{{E_r}}}{{{Z_s}}}\)

           And Zis Synchronous Impedance

F1 Shraddha Jai 16.01.2021 D5F1 Shraddha Jai 16.01.2021 D6

Here, α is torque angle or coupling angle

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