Question
Download Solution PDFIf μ4, = 199, μ3 = 50 and μ2 = 8, then the value of excess kurtosis is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven
μ4 = 199
μ3 = 50
μ2 = 8
Formula
Kurtosis a4= μ4/(μ2)2
Excess kurtosis = a4 – 3
Calculation
a4 = 199/(8)2
⇒ 199/64
⇒ 3.109
⇒ Excess kurtosis is denoted by g2
⇒ g2 = a4 – 3
⇒ 3.109 – 3
∴ Excess kurtosis is 0.109
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