यदि निम्नलिखित घन को खोल दिया जाए, तो वह किस पैटर्न के समान होगा?

F1 Archana  25-2-22 Saivita D8

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RRC Group D Previous Year Paper 72 (Held On: 5 Nov 2018 Shift 2)
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  1. F1 Archana  25-2-22 Saivita D9
  2. F1 Archana  25-2-22 Saivita D10
  3. F1 Archana  25-2-22 Saivita D11
  4. F1 Archana  25-2-22 Saivita D12
    duplicate options found. English Question 1 options 1,2

Answer (Detailed Solution Below)

Option 2 : F1 Archana  25-2-22 Saivita D10
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Detailed Solution

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दिया गया है:
F1 Archana  25-2-22 Saivita D8

यहाँ अनुसरण किया गया तर्क है:-

  • आसन्न फलक होने चाहिए:

 61ce73916cbeaa5adf8ecde3 16552034181981

 

विकल्प 1 से:-

  • 61ce73916cbeaa5adf8ecde3 16552034182012और 61ce73916cbeaa5adf8ecde3 16552034182013 विपरीत हैं, इसलिए यह सही नहीं है।

F1 Archana  25-2-22 Saivita D17

विकल्प 2 से:-

  • यह सही घन स्वरुप है।

F1 Archana  25-2-22 Saivita D18

विकल्प 3 से:-

  • विकल्प 3 में आकृति को मोड़ने पर निम्नलिखित घन प्राप्त होता है और इसलिए सही नहीं है:

F4 Savita Railways 14-7-22 D2

 

विकल्प 4 से:-

  • विकल्प 4 की आकृति को मोड़ने पर निम्नलिखित घन प्राप्त होता है और इसलिए सही नहीं है:

F4 Savita Railways 14-7-22 D1

अत: सही उत्तर "विकल्प 2" है।

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