2.5 kΩ के प्रतिरोध के पार (V) में विभवांतर ज्ञात कीजिए, जिसके माध्यम से 2 mA की धारा प्रवाहित होती है।

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RRB ALP Fitter 23 Jan 2019 Official Paper (Shift 1)
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  1. 5
  2. 0.2
  3. 1.25
  4. 0.8

Answer (Detailed Solution Below)

Option 1 : 5
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धारणा:

  • ओम का नियम: यह बताता है कि स्थिर तापमान और अन्य भौतिक मात्राओं पर विद्युत विभवांतर एक चालक के माध्यम से बहने वाले विद्युत धारा के सीधे आनुपातिक होता है।

इसलिए V = I R

जहां V विभवांतर है, I विद्युत धारा है और R प्रतिरोध है

गणना:

दिया हुआ है कि:

प्रतिरोध (R) = 2.5 kΩ = 2500 Ω 

धारा (I) = 2 mA = 0.002 A

V = IR

V = 2500 × 0.002

V = 5.0

विभवांतर = 5V

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