स्पैन 20 m और उठाव 4 m के तीन-हिंजित वाले परवलयिक आर्क बाएं समर्थन 'A' से 4 m पर 150 kN का एक सकेंद्रित भार वहन करता है। समर्थन 'A' पर क्रमशः ऊर्ध्वाधर प्रतिक्रिया और क्षैतिज थ्रस्ट की गणना करें।

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SSC JE CE Previous Year Paper 9 (Held on 30 Oct 2020 Morning)
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  1. VA = 40 kN और HA = 80 kN
  2. VA = 75 kN और HA = 120 kN
  3. VA = 80 kN और HA = 50 kN
  4. VA = 120 kN और HA = 75 kN

Answer (Detailed Solution Below)

Option 4 : VA = 120 kN और HA = 75 kN
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गणना:

F1 Abhishek M 02-11-21 Savita D2

ΣV = 0, VA + VB = 150 kN

ΣH = 0, HA = H= H

समर्थन B पर, ΣMB = 0

V× 20 - 150 × 16 = 0

VA = 120 kN

V= 150 - 120 = 30 kN

केंद्रीय हिंजित पर, ΣMC = 0

VA × 10 - H × 4 - 150 × 6 = 0

H × 4 = 120 × 10 - 150 × 6

H = 75 kN

तो A पर ऊर्ध्वाधर प्रतिक्रिया और क्षैतिज थ्रस्ट क्रमशः 120 kN और 75kN हैं।

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