Question
Download Solution PDFFind the support reactions acting on the given simply supported beam of length 6 m, which is subjected to a uniformly distributed load of intensity 20 kN/m on the left half span as shown in the diagram.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept
As the 2-D beam is in equilibrium, we can apply equilibrium equations to get the support reactions.
Given
Span = 6 m
udl = 20 KN/m at left half span
Calculation
Equilibrium equations
Ey = 0
Ra + Rb = 20 x 3
Ra + Rb = 60 -(1)
- EMz = 0
taking moment about B and equating it to 0
Ra x 6 - 20 x 3 x (3 + 1.5) = 0
Ra = 45 KN (left)
substituting the value of RA in equation, one to get the value of RB,
40 + Rb = 60
Rb = 15 KN (right)
Last updated on May 28, 2025
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