Question
Download Solution PDFFind Geq in the following network.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Conductance in Series:
\(\frac{1}{G_s}=\frac{1}{G_1}+\frac{1}{G_2}+\frac{1}{G_3}+......\frac{1}{G_n}\)
Conductance in Parallel:
GP = G1 + G2 + G3 + ..... Gn
Application:
Given circuit:
Here, 8 S is connected parallel with 4 S and, 6 S is connected series with 12 S
Hence, an equivalent circuit can be drawn as,
Now, 2 S is connected parallel with 4 S, equivalent circuit can be drawn as,
Hence,
\(\frac{1}{G_{eq}}=\frac{1}{12}+\frac{1}{6}=4\ S\)
Last updated on May 12, 2025
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