Question
Download Solution PDFDuring the measurement of voltage, the voltmeter responded with a 0.18-V change when the input was varied by 0.2 V. Find the sensitivity of the instrument.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFconcept:
Sensitivity(S) of instrument is defined as change in output with respect to change in input
S = \(\frac{dV_0}{dV_i}=\frac{Δ V_0}{Δ V_i}\)
Where
V0 = Output voltage of instrument
Vi = Input voltage of instrument
Application:
Given:
ΔV0 = 0.18 V
ΔVi =0.2 V
S = \(\frac{0.18}{0.2}\) = 0.9
Important Points
- For any Instrument, Even for a small change in input there should be a large change in output i.e sensitivity should be higher
- For any disturbances in the system the output should not be affected much i.e sensitivity should be lower.
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