Question
Download Solution PDFAn engine is assumed to be working on ideal Otto cycle with the temperatures at the beginning and end of compression as 27 °C and 327 °C. The air-standard efficiency of the engine is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In an ideal Otto cycle, if the temperatures at the beginning and end of isentropic compression are known, the air-standard efficiency is:
\( \eta = 1 - \frac{T_1}{T_2} \)
Given:
- Initial temperature, \(T_1 = 27^\circ C = 300~K\)
- Final temperature, \(T_2 = 327^\circ C = 600~K\)
Calculation:
\( \eta = 1 - \frac{300}{600} = 0.5 = 50\% \)
Last updated on Jun 7, 2025
-> RRB JE CBT 2 answer key 2025 for June 4 exam has been released at the official website.
-> Check Your Marks via RRB JE CBT 2 Rank Calculator 2025
-> RRB JE CBT 2 admit card 2025 has been released.
-> RRB JE CBT 2 city intimation slip 2025 for June 4 exam has been released at the official website.
-> RRB JE CBT 2 Cancelled Shift Exam 2025 will be conducted on June 4, 2025 in offline mode.
-> RRB JE CBT 2 Exam Analysis 2025 is Out, Candidates analysis their exam according to Shift 1 and 2 Questions and Answers.
-> The RRB JE Notification 2024 was released for 7951 vacancies for various posts of Junior Engineer, Depot Material Superintendent, Chemical & Metallurgical Assistant, Chemical Supervisor (Research) and Metallurgical Supervisor (Research).
-> The selection process includes CBT 1, CBT 2, and Document Verification & Medical Test.
-> The candidates who will be selected will get an approximate salary range between Rs. 13,500 to Rs. 38,425.
-> Attempt RRB JE Free Current Affairs Mock Test here
-> Enhance your preparation with the RRB JE Previous Year Papers.