Question
Download Solution PDFA soil has a liquid limit of 40% and its plasticity index is 10%. The percentage passing through a 4.75 mm sieve is 60% and the percentage passing through a 75 micron sieve is 45%. The soil can be classified as:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Percentage of soil finer than 4.75 mm (fine + sand) = 60 %
Percentage of soil finer than 0.075 mm (fine)= 45 %
So, % of sand is 60 - 45 = 15 %
We know, total soil = gravel + sand + fine
100 = gravel + 45 + 15, So, gravel % = 40 %
As fines ( < 0.075 mm) are less than 50% so soil is coarse grained (either gravel or sand) and gravel percentage is higher than sand, so it will be gravel (G)
As the Percentage of soil finer than 0.075 mm (fine)= 45 %
which is > Fines are more than 12%, so using plasticity chart
Plasticity index (Ip) = 10%
Liquid limit = 40%
Plasticity index corresponding to A-line, Ip1 = 0.73 × (40 - 20) = 14.6 %
Since, IP < IP1.
So point lies below A-line, so it is silty in nature. Hence soil is classified as GM
Last updated on May 28, 2025
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