A current carrying conductor is wrapped eight times around the jaw of a clamp-on meter that reads 50 A. What will be the actual value of the conductor current?

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SSC JE EE Previous Paper 11 (Held on: 24 March 2021 Morning)
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  1. 400 A
  2. 6.25 A
  3. 50 A
  4. 12.5 A

Answer (Detailed Solution Below)

Option 2 : 6.25 A
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Detailed Solution

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Concept:

Current transformer:

  • A current transformer is a device that is used to measure high alternating current in a conductor.
  • In the figure shown below the conductor act as the primary winding of a single turn that passed through the circular laminated iron core.
  • The secondary winding consists of a large number of turns of fine wire wrapped around the core.
  • Due to transformer action, the secondary current transforms into a lower value.

F1 Harish Batula 13.5.21 Pallavi D14

Let, Np is a number of turn in the primary winding

Ns is the number of turns in the secondary winding.

Ip and Is are primary and secondary turns respectively.

Therefore, the secondary current is given by,

\({I_s} = {I_p} × \frac{{{N_p}}}{{{N_s}}}\)

 
  • Therefore, the current transformer changes the current into a lower value that can easily be measured by the measuring instrument.
  • Along with a Potential transformer (PT), a current transformer (CT) can measure Power and energy also.
  • Hence, CT used with Ammeter, Wattmeter, and Watt-hour meter.
     

​Calculation:

Given, Np = 1, Ns = 8, Ip = 50 A

\({I_s} = {I_p} × \frac{{{N_p}}}{{{N_s}}}\)

Is = 50 × (1 / 8)

Is = 6.25 A

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