Question
Download Solution PDFA 100 V carrier wave is made to vary between 160 V and 40 V by a modulating signal. What is the modulation index?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Modulation index is given as:
\(\Rightarrow {\rm{\mu }} = \frac{{{{\rm{A}}_{{\rm{max}}}} - {{\rm{A}}_{{\rm{min}}}}}}{{{{\rm{A}}_{{\rm{max}}}} + {{\rm{A}}_{{\rm{min}}}}}} = \frac{{{{\rm{V}}_{{\rm{max}}}} - {{\rm{V}}_{{\rm{min}}}}}}{{{{\rm{V}}_{{\rm{max}}}} + {{\rm{V}}_{{\rm{min}}}}}}\)
where Vmax is the maximum voltage and
and Vmin is the minimum voltages.
Calculation:
\(\Rightarrow {\rm{\mu }} = \frac{{160 - 40}}{{160 + 40}} = \frac{{120}}{{200}}\)
∴ μ = 0.6Last updated on May 23, 2025
-> JEE Main 2025 results for Paper-2 (B.Arch./ B.Planning) were made public on May 23, 2025.
-> Keep a printout of JEE Main Application Form 2025 handy for future use to check the result and document verification for admission.
-> JEE Main is a national-level engineering entrance examination conducted for 10+2 students seeking courses B.Tech, B.E, and B. Arch/B. Planning courses.
-> JEE Mains marks are used to get into IITs, NITs, CFTIs, and other engineering institutions.
-> All the candidates can check the JEE Main Previous Year Question Papers, to score well in the JEE Main Exam 2025.