Maths MCQ Quiz in मल्याळम - Objective Question with Answer for Maths - സൗജന്യ PDF ഡൗൺലോഡ് ചെയ്യുക

The correct answer is option 1: Decreasing exponential. The liquid’s temperature decreases by a fixed percentage (10%) each hour, which indicates exponential decay. This situation is best modeled by a decreasing exponential function because the temperature reduces by a constant proportion over time. Option 2 would imply a fixed amount of temperature loss each hour, which is not the case here. Options 3 and 4 describe increasing trends, which do not fit the cooling scenario.

To find the median, list the scores in ascending order, which is already done: 55, 60, 65, 70, 75, 80, 85. The median is the value in the middle of a data set. With 7 values, the median is the 4th number, which is 70. Therefore, option 2 (70) is correct. Options 1 (65), 3 (75), and 4 (80) are incorrect because they do not represent the middle value in the ordered list.

The initial number of users is 5,000 and the number doubles every 6 months. In terms of years, this is equivalent to $2t$ since doubling occurs every half year. Therefore, the equation for the number of users $U$ after $t$ years is $U=5000(2{)}^{2t}$. Option 3 correctly represents this relationship. Option 1 is incorrect because it suggests doubling every month, not every 6 months. Option 2 is incorrect because it implies doubling every 6 years. Option 4 is incorrect because it suggests doubling every year, not 6 months.

To find the equation of a line parallel to $y=4x+2$, we must use the same slope, which is $4$. A parallel line will also have a slope of $4$. The point given is $(3,9)$, and we can use the point-slope form of a line: $y-y_1=m(x-x_1)$. Substituting the values, we get $y-9=4(x-3)$. Simplifying, $y-9=4x-12$, so $y=4x-3$. Thus, the equation is $y=4x-3$, making option 2 correct. Options 1, 3, and 4 are incorrect as they do not satisfy both the condition of passing through $(3,9)$ and having the slope $4$.

Let $x$ represent the number of cows and $y$ represent the number of chickens. We know that cows have 4 legs and chickens have 2 legs. Therefore, the equations are: $x+y=50$ and $4x+2y=140$. Solving these equations, we first multiply the first equation by 2: $2x+2y=100$. Subtracting this from the second equation gives $4x+2y-2x-2y=140-100$, which simplifies to $2x=40$. Dividing by 2, we find $x=20$. Therefore, the farmer has 20 cows.

Subtract $15$ from both sides of $4z+15=47$ to get $4z=32$. Divide both sides by $4$ to solve for $z$, giving $z=8$. Thus, option 1 is correct. Options 2, 3, and 4 are incorrect since they do not satisfy the equation when substituted for $z$.

To solve the equation $3x+12=30$, we first need to isolate the variable $x$. Start by subtracting $12$ from both sides to obtain $3x=18$. Next, divide both sides by $3$ to solve for $x$, yielding $x=6$. Therefore, the value of $x$ is $6$. Option 3 is the correct answer. Options 1, 2, and 4 are incorrect because substituting $x=4,5,$ or $7$ into the equation $3x+12$ does not equal $30$.

The correct answer is 27.

It's given that a triangular prism has a volume of 216 cubic centimeters (cm3) and the volume of a triangular prism is equal to Bh, where B is the area of the base and h is the height of the prism.
Therefore, 216 = Bh. It's also given that the triangular prism has a height of 8 cm.
Therefore, h = 8.
Substituting 8 for h in the equation 216 = Bh yields 216 = B(8).
Dividing both sides of this equation by 8 yields 27 = B.
Therefore, the area, in cm2, of the base of the prism is 27 .

To find q, we start with the equation: $480=(1+\frac{q}{100})\cdot 80$. Dividing both sides by 80 gives $6=1+\frac{q}{100}$. Subtracting 1 from both sides, we have $5=\frac{q}{100}$. Multiplying by 100 gives $q=500$. Thus, the value of q is 500.

To calculate the average (mean), sum all the values and divide by the number of values. The sum of the number of siblings is 0 + 1 + 2 + 1 + 3 + 2 + 4 + 2 + 1 = 16. There are 9 students, so the average number of siblings is 16/9, which is approximately 1.8.