Clock and Calendar MCQ Quiz - Objective Question with Answer for Clock and Calendar - Download Free PDF

Given: 6th day of a month is 2 days earlier than Thursday.

So, (6th day + 2 days) 6th day of the month is → Thursday - 2 → Tuesday

According to the question, 18th day of the month will be:

Odd no of days = (18 - 6) ÷ 7 → 5 odd days

18th day of the month = Tuesday + 5 → Sunday

Hence, "Option 3" is the correct answer.

Given time: 50 minutes past 4 → 4 : 50

Angle traced = 11/2 × Number of Minutes - 30 × Number of Hours

Angle traced = 11/2 × 50 - 30 × 4

Angle traced = 155°

Hence, "Option 3" is the correct answer.

Additional Information
 Movement of Hour head

12 hr = 360º

1 hr = 30º

60 min = 30º

1 min = 0.5º

Movement of Minute head       

1 hr =  360º

60 min = 360º

1 min = 6º   

5 min = 30º     

Movement of Seconds head       

1 min =  360º

60 sec = 360º

1 sec = 6º   

5 sec = 30º

Gapping between hour head and minute head

​55 min = 60 min       

1 min = 60/55 

Given:

The analogue clock is divided into 12 sectors, 1 – 12. One sector represents 30 degrees (360/12 = 30).

If the hour hand is at 10, and the minute hand is at 20, which means there are 6 sectors of 30 degrees each.

Therefore, the hour and minute hand is 180° apart from each other but, at 10:20 hrs hour hand must have travelled some degrees.

Thus, to find the exact angle we use the following formula.

Angle = \(\left| {30H - \frac{{11}}{2}M} \right|\)

Here, H is time in hour and M is time in minutes.

Therefore, we have time 10:20 hrs, H = 10, M = 20.

We get 300 – 110 = 190 which is reflex angle.

NOTE: The reflex angle is the angle which measures greater than 180°.

Thus, 360 – 190 = 170

Hence, the correct answer is "Option 1".

Given:

August 1st, 1975 was a Friday, 

Find the number of odd days from August 1st, 1970 to August 1st, 1975.

Number of years = 1975 - 1970 = 5 years.

Leap years between 1970 and 1975 is 1972 only.

Number of ordinary years = 5 - 1 = 4.

Number of odd days = (Number of ordinary years × 1) + (Number of leap years × 2)

Number of odd days = (4 × 1) + (1 × 2) = 4 + 2 = 6 odd days.

So, August 1st, 1975 was 6 days after August 1st, 1970.

Given that August 1st, 1975 was Friday.

Day of August 1st, 1970 = Friday - 6 days = Saturday.

Therefore, August 1st, 1970 was a Saturday.

Now, find the number of odd days from August 1st, 1970 to September 30, 1970.

Days remaining in August 1970 = 31 - 1 = 30 days.

Days in September 1970 = 30 days.

Total odd days from August 1st, 1970 to September 30, 1970 =

(30 + 30) ÷ 7

= 4 odd days.

Day of September 30, 1970 = Day of August 1st, 1970 + Number of odd days

Day of September 30, 1970 = Saturday + 4 days.

= Wednesday.

Thus, September 30, 1970 was a Wednesday.

Hence, the correct answer is "Option 4".

Given :

The clock shows the time = 10: 20

Concept used :

For mirror image

(11 - hours) : (60 - minutes)

Hours = 10

Minutes = 20

Mirror image = (11 - 10) : (60 - 20)

⇒ Mirror image = 1:40

Hence, the correct answer is "Option 2".

Given : Year 2003 = (Leap year + 3)  = 2000 + 3

Explanation : 

In case of a repeating year, we add (11) to the given year :

So, 

2003 + 11 ⇒ 2014

Hence, "2014" is the correct answer.

Additional Information 

•  Trick to remember:

Odd days:
A leap year has 366 days and a non-leap year has 365 days.

Leap year = 366 days or 52 weeks and 2 days. So, here the number of odd days are 2.

Non - Leap year = 365 days or 52 weeks and 1 day. So, here the number of odd days is 1.

Number of odd days in the following years

Total number of odd days in all the years combined = 1+1+1+2 = 5

 8th February 2020  was Saturday

Code for Saturday is 6 and the number of odd days in all the years combined is 5. So, 6 - 5 = 1

1 is the code for Monday.

Hence, 1^st February 2016 was Monday.

Given : Year - 2033

Explanation:

Calculating the odd days for 31st December 2032 :

2032 can be written as → (2000 + 32) so,

2000 → 0

And,

32 → Dividing 32 by 4 will give get quotient 8 i.e:

Now, 40 ÷ 7 = Remainder = 5

As 5 is the code for Friday , thus it is Friday on 31st December 2032.

And, 

1st January is one day after 31st December 2032, so it will be Saturday.

Hence, "Saturday" is the correct answer.

 Additional Information

1. Ordinary year (365 days) = 1 odd day
2. Leap year (366 days) = 2 odd days

• Number of odd days for the days of week.

• Number of odd days for the days of months.

• Number of odd days for the years.

Note - Any multiple year of 400 like 800, 1200,1600, 2000 etc will have '0' Odd days.

Given: 11th August 2004 = Friday.

Now,

Total days between 11th August 2004 to 11th February 2006

= 20(Aug) + 30(Sept) + 31(Oct) + 30(Nov) + 31(Dec) + 365(2005) + 31(Jan) + 11(Feb) = 549 days.

And, 549/7 = 78 week and 3 odd days.

So, 11th February 2006 = Friday + 3 = Monday.

Hence, the correct answer is "Monday".

Given, at 3 pm

Now at 3.40 pm

In every 5 minutes movement minute hand will make an angle of 30°, thus between 3.30 pm and 3.40 pm it will make an angle of 60° (5 min. + 5 min. = 30° + 30° )

Therefore minute hand is pointing 60° west (9) of the south (6).

Consider, 

Monday= 1

Tuesday = 2

Wednsday = 3

Thursday = 4

Friday = 5 

Saturday = 6

Sunday = 7

As 2000 is divisible by 400 the number of odd days is 0.

Number of leap years till 2016 = 4 (2004, 2008, 2012 and 2016)

Number of ordinary years till 2016 = 12

Number of odd days till 2016 = 12 + (4 × 2) = 20 odd days

Number of odd days in January, 2017 = 3

Number of odd days in February, 2017 = 0

Total number of odd days till 8^th March 2017 = 20 + 3 + 8 = 31 odd days = 3 odd days

Odd days:

A non-leap year has 365 days and a leap year has 366 days.

Non-leap year = 365 days or 52 weeks and 1 day. So, here the number of odd days is 1.

Leap year = 366 days or 52 weeks and 2 days So, here the number of odd days are 2.

Leap year between 2000 to 2012 = 2004, 2008 and 2012

And,

The non-leap year between 2000 and 2012 = 2001, 2002, 2003, 2005, 2006, 2007, 2009, 2010 and 2011

So, total number of odd day between 2000 and 2012 = 9 (Total Non- leap year) + 2 + 2 + 2 = 15 days = 1 odd day

19 July 2000 was a Wednesday

=> Day on 19 July 2012 = Wednesday + 15

= Wednesday + remainder of 15/7

= Wednesday + 1 (odd day) = Thursday

Therefore, 19 July 2012 = Thursday

Now,

15 June 2012 = 19 July 2012 – 34 days

= Thursday – 34

= Thursday – the remainder of 34/7

= Thursday – 6 (In reverse direction)

= Friday

Hence, 15 June 2012 was “Friday”.

At 3:30 p.m., the minute hand of a clock points towards East.

similarly,

The hour hand at 9:00 p.m. will point towards South.

Hence, 'South' is the correct answer.

The correct answer is option(1)

In any two consecutive ordinary years, date of the next year will be one day ahead of the same date of the previous year.

14 January 2022 = Friday

14 January 2023 = Saturday

14 January 2024 = Sunday

If an ordinary year comes immediately after a leap year, then the day on a certain date of the ordinary year will be 2 days ahead of the same date of the leap year upto February

14 January 2025 = Tuesday

From 14 January 2025 to 28 February 2025 = 45 days (42 + 3)

Number of odd days = 3 days

Therefore, 28 February = Friday (3 days ahead from Tuesday)

Hence, the correct answer is Option(1)

The pattern followed here is:

The total number of odd days is listed below:

Therefore 2015 will be the repeated calendar of 2009.Shortcut Trick

So, 2008 + 1 = 2009 + 6 = 2015

So, 2015 is the same as the calendar for the year 2009

Hence, the correct answer is "2015".