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The value of \(\frac{1−\tan^2 45^{\circ}}{1+\tan^2 45^{\circ}}\) is

This question was previously asked in
Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. tan 90°
  2. 1
  3. sin 45°
  4. 0

Answer (Detailed Solution Below)

Option 4 : 0
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Detailed Solution

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Calculations:

tan45° = 1

Hence, The Value of  \(\frac{1−\tan^2 45^{\circ}}{1+\tan^2 45^{\circ}}\) = (1 - 1)/(1 + 1) = 0

Hence, The Correct Answer is option 4.

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