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If sin A = \(\frac{3}{4}\), find the value of cos A.

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Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. \(\frac{4}{3}\)
  2. \(\frac{\sqrt{7}}{4}\)
  3. \(\frac{4}{\sqrt{7}}\)
  4. \(\frac{3}{\sqrt{7}}\)

Answer (Detailed Solution Below)

Option 2 : \(\frac{\sqrt{7}}{4}\)
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Detailed Solution

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Calculations:

sin A = P/H = Perpendicular/Hypotenuse = 3/4 

By Pythagoras Theorem 

(H)2 = (P)2 + (B)2 

= 42 = 32 + B2

16 - 9 = B2

B(Base) = √7

CosA = B/H = √7/4

Hence, The Correct Answer is option 2.

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