10% चक्रवाढ व्याजाने दरवर्षी व्याज जोडल्यास, 12,000 रुपये किती वर्षात 14,520 रुपये होतील?

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RRB Technician Grade III Official Paper (Held On: 29 Dec, 2024 Shift 1)
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  2. 5
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Answer (Detailed Solution Below)

Option 1 : 2
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Detailed Solution

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दिलेल्याप्रमाणे:

मुद्दल (P) = 12,000 रुपये 

रास (A) = 14,520 रुपये 

दर (r) = 10% वार्षिक

वापरलेले सूत्र:

A = P(1 + )t

गणना:

14,520 = 12,000(1 + )t

= (1 + )t

⇒ 1.21 = (1.1)t

⇒ 1.12 = (1.1)t

⇒ t = 2

म्हणूनच योग्य उत्तर पर्याय (1) आहे.

Latest RRB Technician Updates

Last updated on Jul 23, 2025

-> The Railway RRB Technician Notification 2025 released under the CEN Notification - 02/2025.

-> As per the Notice, around 6238 Vacancies is  announced for the Railway RRB Technician 2025 Recruitment. 

-> A total number of 45449 Applications have been received against CEN 02/2024 Tech Gr.I & Tech Gr. III for the Ranchi Region.

-> The last date to apply online for Railway RRB Technician 2025 is 28th July 2025. Candidates applying for the Grade I & Grade III posts submit their applications on or before that.  

-> The Pay scale for Railway RRB Technician posts ranges from Rs. 19900 - 29200.

-> Prepare for the exam with RRB Technician Previous Year Papers.

-> Candidates can go through RRB Technician Syllabus and practice for RRB Technician Mock Test.

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