Question
Download Solution PDFIn which one of the following equilibria, Kp ≠ Kc?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
We know that, KP = Kc(RT)∆ng
KP and Kc are equilibrium constant.
R is gas constant
T is temperature
∆ng is differences of moles.
∴ If ∆ng ≠ 0 then Kp ≠ Kc
Now, 2C (s) + O2 (g) ⇌ 2CO (g)
∆ng = +1
∴ KP = Kc (RT)1
Hence, Kp ≠ KcLast updated on May 23, 2025
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