In the measurement of RMS value of a voltage in CRO, the peak-to-peak voltage is divided by which of the following values?

This question was previously asked in
SSC JE Electrical 06 Jun 2024 Shift 2 Official Paper - 1
View all SSC JE EE Papers >
  1. \(2\sqrt2\)
  2. \(\frac{2}{\sqrt2}\)
  3. \(\frac{1}{\sqrt2}\)
  4. \(\sqrt2\)

Answer (Detailed Solution Below)

Option 1 : \(2\sqrt2\)
Free
Electrical Machine for All AE/JE EE Exams Mock Test
7.4 K Users
20 Questions 20 Marks 20 Mins

Detailed Solution

Download Solution PDF

In the measurement of RMS (Root Mean Square) value of a voltage using a CRO (Cathode Ray Oscilloscope), the peak-to-peak voltage is divided by \(2\sqrt2\).

This is because:

  • Peak-to-peak voltage (Vpp) represents the full voltage swing from the maximum positive to the maximum negative value.
  • The peak voltage (Vp) is half of the peak-to-peak voltage: \(V_p={V_{pp}\over 2}\)
  • The RMS value for a sinusoidal waveform is related to the peak voltage by: \(V_{RMS}={V_{p}\over \sqrt{2}}\)


Combining these, the relationship between the RMS voltage and the peak-to-peak voltage is:

\(V_{RMS}={V_{pp}\over 2\sqrt{2}}\)

Latest SSC JE EE Updates

Last updated on May 29, 2025

-> SSC JE Electrical 2025 Notification will be released on June 30 for the post of Junior Engineer Electrical/ Electrical & Mechanical.

-> Applicants can fill out the SSC JE application form 2025 for Electrical Engineering from June 30 to July 21.

-> SSC JE EE 2025 paper 1 exam will be conducted from October 27 to 31. 

-> Candidates with a degree/diploma in engineering are eligible for this post.

-> The selection process includes Paper I and Paper II online exams, followed by document verification.

-> Prepare for the exam using SSC JE EE Previous Year Papers.

Get Free Access Now
Hot Links: all teen patti teen patti master real cash teen patti game online teen patti gold new version teen patti octro 3 patti rummy