Question
Download Solution PDFIf \(\rm \frac{x}{y}=\frac{3}{5}\), then \(\frac{5x+2y}{5x-2y}\) is equal to
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
\(\dfrac{x}{y}=\dfrac{3}{5}\)
Calculation:
\(\dfrac{5x+2y}{5x-2y}\)
Let \(x = 3k\) and \(y = 5k\)
⇒ \(\dfrac{5(3k) + 2(5k)}{5(3k) - 2(5k)}\)
⇒ \(\dfrac{15k + 10k}{15k - 10k}\)
⇒ \(\dfrac{25k}{5k}\)
⇒ 5
∴ The correct answer is option (2).
Last updated on Jun 30, 2025
-> TNPSC Group 1 Result and Final Answer Key 2025 will be released soon by the commission.
-> TNPSC Group 1 Answer Key 2025 has been released at tnpsc.gov.in.
-> TNPSC Group 1 Admit Card 2025 has been released at tnpsc.gov.in.
-> TNPSC Group 1 Notification 2025 has been released for 72 vacancies on its official website on 1 April 2025.
-> TNPSC Group 1 apply online for 2025 from 1 April to 30 April 2025. And candidates can download their hall ticket in the 1st week of June 2025.
-> TNPSC Group 1 Prelims exam date has been announced. The exam is going to be conducted on 15 June 2025.
-> The Selection of the candidates is based on their performance in the prelims, mains, and interviews.
-> The candidates must buckle up and give their preparation a boost by practicing TNPSC Group 1 Previous Year Papers.