Question
Download Solution PDFComprehension
The following table shows the percentage (%) distribution of number of students qualifying an Entrance Exam from seven schools A-G in the years 2020 and 2021. The number of students qualifying from School G in 2020 and 2021 are 90 and 135, respectively. Based on the data in the table, answer the questions:
School-wise Distribution of Qualified Students
| School | Distribution (%) of Qualified students | |
| 2020 | 2021 | |
| A | 21% | 23% |
| B | 14% | 8% |
| C | 16% | 11% |
| D | 10% | 14% |
| E | 18% | 16% |
| F | 9% | 13% |
| G | 12% | 15% |
If P and Q are the average number of students qualifying from Schools B, C and D in 2020 and from Schools E, F and G in 2021, respectively, then Q - P is
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFFormula
Average = total sum of all values/No. of values.
A % B = A/B × 100
Solution
Let the total number of students qualified in 2020 be 100x.
⇒ 12x = 90
⇒ x = 7.5
| School | Qualified student(2020) | Total |
| B | 14x | 14 × 7.5 = 105 |
| C | 16x | 16 × 7.5 = 120 |
| D | 10x | 10 × 7.5 = 75 |
The average number of students qualifying from Schools B, C and D in 2020:
⇒ P = (105 + 120 + 75)/3 = 100
Let the total number of students qualified in 2021 be 100y.
⇒ 15y = 135
⇒ y = 9
| School | Qualified student(2021) | Total |
| E | 16y | 16 × 9 = 144 |
| F | 13y | 13 × 9 = 117 |
| G | 15y |
15 × 9 = 135 |
The average number of students qualifying from Schools E, F and G in 2020:
⇒ Q = (144 + 117 + 135)/3 = 132
Hence, Q - P = 132 - 100 = 32
Last updated on Jun 22, 2025
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