Question
Download Solution PDFयदि द्विध्रुव को वायु या निर्वात में रखा जाए तो लघु द्विध्रुव के कारण बिंदु P पर विद्युत क्षेत्र की तीव्रता क्या होगी?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
वायु या निर्वात में एक छोटा द्विध्रुव
संकल्पना:
एक विद्युत द्विध्रुव एक छोटी दूरी पर रखे समान और विपरीत परिमाण के दो-बिंदु आवेशों की एक प्रणाली है।
सूत्र:
एक द्विध्रुवीय, द्विध्रुवीय आघूर्ण के लिए,
p = q(2l)
गणना:
E(+q) = \(\frac{q}{4\pi \epsilon 0(r-l)^2}\) BP की ओर
E(-q) = \(\frac{q}{4\pi \epsilon 0(r+l)^2}\) PA की ओर
E = E(+q) - E(-q)
⇒ E = \(\frac{q}{4\pi \epsilon 0(r-l)^2} -\frac{q}{4\pi \epsilon 0(r+l)^2}\)
⇒ E = \(\frac{4qlr}{4\pi \epsilon 0(r^2-l^2)^2}\)
⇒ E = \(\frac{2q(2l)r}{4\pi \epsilon 0(r^2-l^2)^2}\)
लेकिन q(2l) = p और एक लघु द्विध्रुव r2 - l2 ≈ r2 के लिए l << r के रूप में
⇒ E = \(\frac{2pr}{4\pi \epsilon 0r^4}\)
⇒ E = \(\frac{2p}{4\pi \epsilon 0r^3}\)
Last updated on May 26, 2025
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