Question
Download Solution PDFm के किस मान के लिए समीकरण निकाय 17x + my + 102 = 0 और 23x + 299y + 138 = 0 के अनंत हल होंगे?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
समीकरणों के निकाय 17x + my + 102 = 0 और 23x + 299y + 138 = 0 के अनंत हल हैं।
प्रयुक्त अवधारणा:
जब Ax + By = C और Px + Qy = R एक रैखिक समीकरण निकाय बनाते हैं, तो इसके अपरिमित रूप से अनेक हल होते हैं, यदि,
A/P = B/Q = C/R
गणना:
चूँकि दिए गए रैखिक समीकरण निकाय के अनंत हल हैं, इसलिए,
अवधारणा के अनुसार,
17/23 = m/299 = 102/138
अतः,
17/23 = m/299
⇒ m = (17 × 299) ÷ 23
⇒ m = 221
∴ m का मान 221 है।
Last updated on Jun 13, 2025
-> The SSC CGL Notification 2025 has been released on 9th June 2025 on the official website at ssc.gov.in.
-> The SSC CGL exam registration process is now open and will continue till 4th July 2025, so candidates must fill out the SSC CGL Application Form 2025 before the deadline.
-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.
-> Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.
-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline.
-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> Candidates should also use the SSC CGL previous year papers for a good revision.