आव्यूह A = \(\left[\begin{array}{cc}2 & 1 \\ -3 & 0\end{array}\right]\) का योगात्मक प्रतिलोम ज्ञात कीजिए। 

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Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. A = \(\left[\begin{array}{cc}2 & 1 \\ −3 & 0\end{array}\right]\)
  2. −A = \(\left[\begin{array}{cc}−2 & −1 \\ 3 & 0\end{array}\right]\)
  3. 2A = \(\left[\begin{array}{cc}4 & 2 \\ −6 & 0\end{array}\right]\)
  4. इनमें से कोई नहीं

Answer (Detailed Solution Below)

Option 2 : −A = \(\left[\begin{array}{cc}−2 & −1 \\ 3 & 0\end{array}\right]\)
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Bihar STET Paper 1 Mathematics Full Test 1
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Detailed Solution

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प्रयुक्त अवधारणा:

2 × 2 क्रम के आव्यूह \(\left[\begin{array}{cc}a & b \\ c & d\end{array}\right]\) का निर्धारक = \(-\left[\begin{array}{cc}a & b \\ c & d\end{array}\right]\)  

गणना:

आव्यूह A का समायोजन = \(\left[\begin{array}{cc}2 & 1 \\ −3 & 0\end{array}\right]\) 

आव्यूह A का योगात्मक प्रतिलोम = - \(\left[\begin{array}{cc}2 & 1 \\ −3 & 0\end{array}\right]\) = \(\left[\begin{array}{cc}−2 & −1 \\ 3 & 0\end{array}\right]\)

अतः, इनमें से 2 सही  है।

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