Question
Download Solution PDFFind the value of \(\rm \frac{1.2\times 1.2\times 1.2-0.2\times 0.2\times 0.2}{1.2\times 1.2+1.2\times 0.2+0.2\times 0.2}\)
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Find the value of \(\rm \frac{1.2\times 1.2\times 1.2-0.2\times 0.2\times 0.2}{1.2\times 1.2+1.2\times 0.2+0.2\times 0.2}\)
Formula used:
(a3 - b3) / (a2 + ab + b2) = a - b
Where, a = 1.2 and b = 0.2
Calculations:
(1.2 × 1.2 × 1.2 - 0.2 × 0.2 × 0.2) / (1.2 × 1.2 + 1.2 × 0.2 + 0.2 × 0.2)
⇒ (1.23 - 0.23) / (1.22 + 1.2 × 0.2 + 0.22)
⇒ (1.2 - 0.2)
⇒ 1
∴ The correct answer is option 2.
Last updated on Jun 23, 2025
-> TNPSC Group 1 Answer Key 2025 has been released at tnpsc.gov.in.
-> TNPSC Group 1 Admit Card 2025 has been released at tnpsc.gov.in.
-> TNPSC Group 1 Notification 2025 has been released for 72 vacancies on its official website on 1 April 2025.
-> TNPSC Group 1 apply online for 2025 from 1 April to 30 April 2025. And candidates can download their hall ticket in the 1st week of June 2025.
-> TNPSC Group 1 Prelims exam date has been announced. The exam is going to be conducted on 15 June 2025.
-> The Selection of the candidates is based on their performance in the prelims, mains, and interviews.
-> The candidates must buckle up and give their preparation a boost by practicing TNPSC Group 1 Previous Year Papers.