Two infinite parallel conductors carry currents of '20 A' each. The magnitude of the force between the conductor per metre length if the distance between them is '20 cm' is __________.

Concept:

The magnitude of the force between the conductor is given by

\(F = \frac{\mu_{0}I_{1}I_{2}l}{2\pi d} = 2 \times 10^{-7} \times \frac{I_{1}I_{2}l}{d} \)

Where;

I_1,2 → current carried by the conductors 

l → Length

d→ Distance between conductors

Calculation:

Given;

I1,2 → current carried by the conductors = 20 A

d→ Distance between conductors = 20 cm = 0.2 m

Then;

The magnitude of the force per meter between the conductor is given by;

\(\frac{F}{l} = \frac{\mu_{0}I_{1}I_{2}}{2\pi d} = 2 \times 10^{-7} \times \frac{I_{1}I_{2}}{d}= 2 \times 10^{-7} \times \frac{20 \times 20}{0.2}=4 \times 10^{-4} \, N\)