Question
Download Solution PDFThe power gain in decibels can be expressed as:
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KVS TGT WET (Work Experience Teacher) Official Paper
Answer (Detailed Solution Below)
Option 2 : \(10 \ln\left(\frac{P_o}{P_i} \right)\)
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KVS TGT Mathematics Mini Mock Test
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Detailed Solution
Download Solution PDFPower gain is the ratio of the output power (P0) to the input power (Pin), i.e.
\({A_p} = \frac{{{P_0}}}{{{P_{in}}}}\)
In terms of dB, the power gain is expressed as:
\(P(dB) = 10\log_{10}{\frac{P_{out}}{P_{in}}}\)
Property: logx x = 1
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