Question
Download Solution PDFThe mechanical efficiency of a single-cylinder, four-stroke engine is 75%. If friction power is 37.5 kW, then what will be the brake power developed by the engine?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The mechanical efficiency of the engine is given by:
\(\eta_{mech} = \frac{BP}{IP} = \frac{BP}{BP + FP}\)
where IP = Indicated Power of Engine, BP = Brake Power, FP = Frictional Power
Calculation:
Given:
FP = 37.5 kW, η = 75%
\(\frac{75}{100} = \frac{BP}{BP + 37.5}\)
0.75(BP + 37.5) = BP
BP = 112.5 kW
Last updated on Sep 23, 2024
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