The distance between the points (2, 3) and (4, 1) is. 

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Bihar STET TGT (Maths) Official Paper-I (Held On: 04 Sept, 2023 Shift 1)
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  1. 2
  2. 1
  3. 2√2
  4. \(\sqrt{52}\)

Answer (Detailed Solution Below)

Option 3 : 2√2
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Bihar STET Paper 1 Mathematics Full Test 1
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Detailed Solution

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Formula Used:

To find the distance between two points (x1, y1) and (x2, y2) in a Cartesian coordinate system, you can use the distance formula:

Distance (d) = \( \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

Explanation:

In this case, the points are (2, 3) and (4, 1), so you can use these coordinates in the distance formula:

⇒ Distance (d) = \(\sqrt{(4 - 2)^2 + (1 - 3)^2}\)

⇒ Distance (d) = \(\sqrt{(2)^2 + (-2)^2}\)

⇒ Distance (d) = √(4 + 4)

⇒ Distance (d) = √8

⇒ Distance (d) = 2√2

So, the distance between the points (2, 3) and (4, 1) is 2√2 units. 

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